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avatarSupraZinc3154
Secondary V • 9mo.

Hello would anyone be able to explain me this type of chemistry question. I always seem to get these types of questions wrong and I just don’t understand why I’m not getting them.

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Explanations (1)

  • Explanation from Alloprof

    Explanation from Alloprof

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      avatarKylan Tteacher check
      Team Alloprof • 9mo.

      Hi SupraZinc,

      Thanks for your question!

      The ideal gas law is PV = nRT. Therefore, to determine P, you get P = (nRT)/V. Since R is constant, you can get rid of it for the exercice (since you don't need a true value of P, only a size comparison). Therefore, P = (nT)/V.

      The variables you wrote on the right of your picture are a great start! You can replace the variables in the ideal gas law with 1 if they remain unchanged and by 3 if they are trippled.

      So, initially, we have:

      P = (nT)/V = (1*1)/1 = 1

      After the changes:

      P = (3*3)/3 = 3

      So the pressure is tripled!

      You can always use this method for this kind of problem.

      Don't hesitate to reach out again if needed:)

      Kylan

    Québec RioTinto Desjardins Pathy TROTTIER OTHER
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