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The limit law used in this expression is the Product Law.
The Product Law states that
\(\lim_{{x \to a}} [f(x) \times g(x)] = L \times M \)
\(\equiv\)
\( \lim_{{x \to a}} f(x) = L \quad \times \quad \lim_{{x \to a}} g(x) = M \)
In your case, you have two functions\( (x - 2)^6 \)and \( 2x^2 \) being multiplied together, and you find their individual limits first, that's why the product law is used here.
Explanation from Alloprof
This Explanation was submitted by a member of the Alloprof team.
Hi !
The limit law used in this expression is the Product Law.
The Product Law states that
\(\lim_{{x \to a}} [f(x) \times g(x)] = L \times M \)
\(\equiv\)
\( \lim_{{x \to a}} f(x) = L \quad \times \quad \lim_{{x \to a}} g(x) = M \)
In your case, you have two functions\( (x - 2)^6 \)and \( 2x^2 \) being multiplied together, and you find their individual limits first, that's why the product law is used here.
Have a good day :)