In this case, you can solve this as a system of equations. You can assume that y = y to compare both equations as below:
$$ y = y \Rightarrow 2x - 1 = (x+6)^2 + 11 $$
You can then isolate all the equations on one side to have an equation following the format \( 0 = ax^2 + bx + c \). You can then find the value for \( b^2 - 4ac \) to determine of the system will admit one, two or no solutions.
You can follow the link below to look at similar examples:
Explanation from Alloprof
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Hello Red Ruby!
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In this case, you can solve this as a system of equations. You can assume that y = y to compare both equations as below:
$$ y = y \Rightarrow 2x - 1 = (x+6)^2 + 11 $$
You can then isolate all the equations on one side to have an equation following the format \( 0 = ax^2 + bx + c \). You can then find the value for \( b^2 - 4ac \) to determine of the system will admit one, two or no solutions.
You can follow the link below to look at similar examples:
Feel free to reach out if you have any other questions!